Answers

2014-03-18T13:18:57+01:00
5x+3y=1.........................1
2x+3y=-5...........................2
using elimination method,
 eqn.(1) by x2
eqn(2) by x5
10x+6y=2.........................3
10x+15y=-25..................4
sub eqn(4) 4rm eqn(3)
0x-9y=27
     -9y=27
y=27/-9
               y=-3

subtit. y into eqn. (1)
5x+3y=1
:. y=-3
5x+3(-3)=1
5x-9=1
5x=1+9
5x=10
x=10/5
x=2


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