# Calculate the density of carbon dioxide in grams per litre at 0.9900 atm and 55degrees celcius

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P = 0.9900atm

V = ?

n = ?

R = molar gas constant, 0.082atm.dm³.mol⁻¹.K⁻¹

T = (55 + 273)K = 328K

Here we have two unknowns, n and V.

We arrange them both on one side.

=

Remember, n (mol) =

The equation now becomes,

=

=

Multiply both sides by

=

Now again, we have V and mass on one side, and we're solving for density.

But density is equal to mass/volume

If = ,

then =

Therefore, our m/v, which is density, is equal to;

We have extracted all values, except the molar mass.

Molar mass of CO₂ = 12 + (16 × 2) = 44gmol⁻¹

Substituting all values in our equation, we have;

d=

Ah! But density is g/dm³ abi? Yes, 1dm³ = 1L, so our units are still correct.