4.0 moles 0f an ideal gas are at a temperature of -23 degree cecious and a pressure 300mmhg. what volume in dmcube. will the gas occupy at that temperature?. (R=0.082)

2
by danochihu

2014-02-23T00:01:22+01:00
N=PV/NT             V=nRT/P           where n is the mole,V is the volume of the gas,P is the pressure of the gas and T is the temperature of the gas.                                   convert 23 degree celsius to kelvin   23 degree celsius=(273+23)kelvin=296K                    :. V=4.0*0.082*296/300                                                                                                   V=97.088/300                                                                                                              V=0.32
Very incorrect.
2014-02-23T07:16:55+01:00
The ideal gas equation is something like this;
pV = nRT
where,
p = pressure (in atm)
V = volume (in dm³)
n = no. of moles (mol.)
R = molar gas constant, (0.082atm.dm³.mol⁻¹.K⁻¹)
T = absolute temperature (Kelvin)

making V the subject of the formular,
V =

n = 4mol.
R = 0.082atm.dm³.mol⁻¹.K⁻¹
T = (-23 + 273)K = 250K
P = 300mmHg = atm

V =
V = 207.733dm³