Answers

2014-02-22T07:36:56+01:00
Differentiate y = x⁴ + 5x³ - 4x² + 7x - 2 with respect to x.

By the general rule,
If f(x) = ax^n , then f'(x)= anx^(n-1)

f'(x) = (4)(1)x⁴⁻¹ + (5)(3)x³⁻¹ - (4)(2)x²⁻¹ + (7)(1)x¹⁻¹ - 0
f'(x) = 4x³ + 15x² - 8x¹ + 7x° - 0
f'(x) = 4x³ + 15x² - 8x + 7
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